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Potential difference beween centre and s...

Potential difference beween centre and surface of the sphere of radius R and uniorm volume charge density `rho` within it will be

A

`(rhoR^2)/(6epsilon_0)`

B

`(rhoR^2)/(4epsilon_0)`

C

`(rhoR^2)/(3epsilon_0)`

D

`(rhoR^2)/(2epsilon_0)`

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The correct Answer is:
To find the potential difference between the center and the surface of a sphere with radius \( R \) and uniform volume charge density \( \rho \), we can follow these steps: ### Step 1: Calculate the total charge \( Q \) inside the sphere The total charge \( Q \) within a sphere of radius \( R \) with uniform volume charge density \( \rho \) can be calculated using the formula: \[ Q = \rho \cdot V \] where \( V \) is the volume of the sphere given by: \[ V = \frac{4}{3} \pi R^3 \] Thus, we have: \[ Q = \rho \cdot \frac{4}{3} \pi R^3 \] ### Step 2: Calculate the electric potential \( V_c \) at the center of the sphere The electric potential \( V_c \) at the center of a uniformly charged sphere can be calculated using the formula: \[ V_c = \frac{1}{4 \pi \epsilon_0} \cdot \frac{Q}{R} \] Substituting the expression for \( Q \): \[ V_c = \frac{1}{4 \pi \epsilon_0} \cdot \frac{\rho \cdot \frac{4}{3} \pi R^3}{R} \] This simplifies to: \[ V_c = \frac{\rho}{3 \epsilon_0} R \] ### Step 3: Calculate the electric potential \( V_s \) at the surface of the sphere The electric potential \( V_s \) at the surface of the sphere (radius \( R \)) is given by: \[ V_s = \frac{1}{4 \pi \epsilon_0} \cdot \frac{Q}{R} \] Again substituting for \( Q \): \[ V_s = \frac{1}{4 \pi \epsilon_0} \cdot \frac{\rho \cdot \frac{4}{3} \pi R^3}{R} \] This simplifies to: \[ V_s = \frac{\rho}{3 \epsilon_0} R \] ### Step 4: Calculate the potential difference \( V_{diff} \) The potential difference \( V_{diff} \) between the center and the surface of the sphere is given by: \[ V_{diff} = V_c - V_s \] Substituting the values of \( V_c \) and \( V_s \): \[ V_{diff} = \left(\frac{\rho}{3 \epsilon_0} R\right) - \left(\frac{\rho}{3 \epsilon_0} R\right) = 0 \] ### Conclusion The potential difference between the center and the surface of the sphere is: \[ V_{diff} = 0 \]

To find the potential difference between the center and the surface of a sphere with radius \( R \) and uniform volume charge density \( \rho \), we can follow these steps: ### Step 1: Calculate the total charge \( Q \) inside the sphere The total charge \( Q \) within a sphere of radius \( R \) with uniform volume charge density \( \rho \) can be calculated using the formula: \[ Q = \rho \cdot V \] where \( V \) is the volume of the sphere given by: ...
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