At a distance of `5 cm and 10 cm` outward from the surface of a uniformly charged solid sphere, the potentials are `100 V and 75 V`, repectively. Then.

Options

A. potential at its surface is `150 V`
B. the charge on the shre is `50/3xx10^-10C`
C. the electric field on the surface is `1500 V//m`
D. the electric potential at its centre is `25 V`

Answer

A, B, C

Explanation

`100=1/(4piepsilon_0).q/((R+0.05))` …….i
`75=1/(4piepsilon_0).q/((R+0.05))`……..ii
Solving these equations, we get
`q=5/3xx10^-9C`
and `R=0.1m`
a. `V=1/(4piepsilon_0).q/R`
`((9xx10^9)(5/3xx10^-9))/0.1`
`=150V`
c. `E=1/(4piepsilon_0).q/R^2=V/R=150/0.1`
`=1500V//m`
`d. V_(centre)=1.5v_(surface)`