A charged particle projected in a magnetic field
`B=(3hati+4hatj)xx10^-2T`
The acceleration of the particle is found to be
`a=(xhati+2hatj)m/s^2`
find the value of `x`

Explanation

To solve the problem, we will use the relationship between the acceleration of a charged particle in a magnetic field and the properties of the vectors involved.

### Step-by-Step Solution:

1. **Identify Given Quantities**:
- Magnetic field \( \mathbf{B} = (3\hat{i} + 4\hat{j}) \times 10^{-2} \, \text{T} \)
- Acceleration \( \mathbf{a} = (x\hat{i} + 2\hat{j}) \, \text{m/s}^2 \)

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