A square of side `2.0 m` is placed in a uniform magnetic field `B=2.0 T` in a direction perpendicular to the plane of the square inwards. Equal current `i=3.0 A` is flowing in the directions shown in figure. Find the magnitude of magnetic force on the loop.
Text Solution
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Fore on wire `ACD`=Force on `AD =Force` on `AED ` `:.` Net force on the loop `=3(F_(AD))` `=(3)(3.0)(2sqrt(2))(2.0)N=36sqrt(2)N` Direction of this force is towards `EC`.
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