A square loop `OABCO` of side of side `l` carries a current `i`. It is placed as shown in figure. Find the magnetic moment of loop.
Text Solution
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As discussed above, magnetic moment of the loop can be written as `M=i(BCxxCO)` `Here, BC=-lhatk`, `CO=-cos60^I@hati-lsin60^@hatj=l/2hati-sqrt(3l)/2hatj` `:. M=i[(-lhatk)xx(-l/2hati-sqrt(3l)/2hatj)]` or `M=(il^2)/2(hatj-sqrt3hati)`
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