Figure shows a current loop having two circular arcs joined by two lines. Find the magnitude field `B` at the centre `O`.
Text Solution
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Magnetic field at point `O` due to wire `CB` and `AD` will be zero. Magnetic field due to wire `BA` will be `B_1=(theta/(2pi))((mu_0i)/(2a))` Direction of field `B_1` is coming out of the plane of the figure. Similarly, field at `O` due to `DC` will be `B_2=(theta/(2pi))((mu_0i)/(2b))` Direction of field `B_2` is going into the plane of the figure. The resultant field at `O` is `B=B_1-B_2=(mu_0theta(b-a))/(4piab)`
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