A rectangular coil of area `5.0xx10^-4m^2` and `60` turns is pivoted about one of its vertical sides. The coil is in a radial horizontal magnetic field of `9xx10^-3T`. What is the torsional constant of the spring connected to the coil if a current of `0.20mA` produces an angular diflection of `18^@`?
Text Solution
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From the equation, `i=(k/(NAB))phi` We find that torsional constant of the spring is given by `k=(NABi)/phi` Substituting the values is `SI` units we have `k=((60)(5.0xx10^-4)(9xx10^-3)(0.2xx10^-3))/18` `=3xx10^-9N-m//degree`
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