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An infifnitely long conductor PQR is ben...

An infifnitely long conductor `PQR` is bent to form a right angle as shown in figure. A current `I` flows through `PQR`. The magnetic field due to this current at the point `M` is `H_1` Now, another infinitely long straight conductor `QS` is connected at `Q`, so that current is `I/2` in `QR` as well as in `QS`, the current in `PQ` remaining unchanged. The magnetic field at `M` is now `H_2`. The ratio `H_1/H_2` is given by `

A

`1/2`

B

1

C

`2/3

D

2

Text Solution

Verified by Experts

`H_1=` Magnetic field at `M` due to `PQ+`Magnetic field at `M` due to `QR`
but magnetic field at M due to `QR=0`
`:.` Magnetic field at M due to `PQ `(or due to current `I` in `PQ`)
`=H_1`
Now `H_2=`Magnetic fiedl at `M` due to `P` (current `I`)
`+`magnetic field at `M` due to `QS` (current `I/2`) `+` magnetic field at `M` due to `QR`
`=H_1+H_1/2+0=3/2H_1`
`H_1/H_2=2/3`
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