Magnetic field will rotate the particle in as circulr path (in-`xz`-plane or perpendicular to `B`). Electric field exert a constant force to the particle in positive `y`-direction. Therefore, resultannt path is neither purely circular nor helical or the options a and b both are wrong.
c. `v_(_|_)` and `B` will rotate the particle in a circular path in `xz` plane (or perpendicular to `B`). Further, `v_(||)` and `E` will move the particle (with increasing speed) along positive `y`-axis(or along the axis of above circular path). Therefore, the resultant path is helical wilth increasing pitch along the y-axis (or along `B` and `E`). Therefore option c is correct.
Magnetic force is zero, as `theta` between `B` and `v` is zero. But electric force will act in y-direction. Therefore, moto is `1-D` and uniformly accelerated (towards positive y-direction). Therefore, option d is also correct.