A cyclotron's oscillator frequency is `10MHz`. What should be the operating magnetic field fro accelerating protons? If the radius of its dees is `60cm`, what is the kinetic energy (in `MeV`) of the proton beam produced by the acceleration?
`(e-1.60xx10^-19C,m_p=1.67xx10^-27kg, 1MeV=1.6xx10^-13J)`

Explanation

To solve the problem step by step, we will first determine the operating magnetic field of the cyclotron and then calculate the kinetic energy of the proton beam produced by the acceleration.

### Step 1: Determine the Magnetic Field

Given:
- Oscillator frequency, \( f = 10 \text{ MHz} = 10 \times 10^6 \text{ Hz} \)
- Charge of proton, \( Q = 1.6 \times 10^{-19} \text{ C} \)
- Mass of proton, \( m_p = 1.67 \times 10^{-27} \text{ kg} \)
...