What is the value of `B` that can be set up at the equator to permit a proton of speed `10^7m//s` to circulate around the earth? `[R=6.4xx10^6m,m_p=1.67xx10^-27kg]`
Text Solution
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From the relation `r=(mv)/(Bq)` We have `B=(mv)/(qr)` Substituting the vaues we have `B=((1.67xx10^-27)(10^7))/((1.6xx10^-19)(6.4xx10^6))` `=1.6xx10^-8T`
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