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In the Bohr model of the hydrogen atom, ...

In the Bohr model of the hydrogen atom, the electron circuulates around the nucleus in a path of radius `5xx10^-11m` at a frequency of `6.8xx10^15Hz`.
a. What value of magnetic field is set up at the centre of the orbit?
b. What is the equivalent magnetic dipole moment?

Text Solution

Verified by Experts

a. An electron moving around the nucleus is equivalent to a current,
Magnetic field at the centre,
`B=(mu_0i)/(2R)=(mu_0qf)/(2R)`
Substituting the values, we have
`B=((4pixx10^-7)(1.6xx10^-19)(6.8xx10^15))/(2xx5.1xx10^-11)`
`=13.4T`
b. The current carrying circular loop is equaivalent to a magnetic dipole with magnetic dipole moment,
`M=NiA=(NqfpiR^2)`
Substituting the values, we have
`M=(1)(1.6xx10^19)(6.8xx10^15)(3.14)(5.1xx10^-11)^2`
`=8.9xx10^-24A-m^2`
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