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A charged particle moves in a circular p...

A charged particle moves in a circular path in a uniform magnetic field. If its speed is reduced, then its time period will

A

increase

B

decrease

C

remain same

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`T=(2m)/(Bq)`, independent of v.
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Knowledge Check

  • When a charged particle moves in an elecltric or a magnetic field, its speed is v and acceleration is a

    A
    In a magnetic field `v` is constant if the particle moves in a circular path, and variable if it moves in a helical path.
    B
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    C
    In an electric field, `v` can never remain constant.
    D
    In a uniform electric field, `a` must be constant in magnitude and direction.

  • Assertion: A charged particle is moving in a circle with constant speed in uniform magnetic field. If we increase the speed of particle to twice, its acceleration will become four times. Reason: In circular path of radius R with constant speed v , acceleration is given by v^2/R

    A
    If both Assertion and Reason are true and the Reason is correct explanation of the Assertion.
    B
    If both Assertion and Reason are true but Reason is not the correct explanation of Assertion
    C
    If Assertion is true, but the Reason is false.
    D
    If Assertion is false but the Reason is true.

  • Time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of

    A
    speed of the particle.
    B
    mass of the particle.
    C
    charge of the particle.
    D
    magnetic field.

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