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As loop of magnetic moment M is placed i...

As loop of magnetic moment `M` is placed in the orientation of unstable equilbirum position in a uniform magnetic field `B`. The external work done in rotating it through an angle `theta` is

A

`-MB(1-costheta)`

B

`-Mbcostheta`

C

`Mbcostheta`

D

`MB(1-costheta)`

Text Solution

Verified by Experts

The correct Answer is:
A

`theta_i=180^@, theta_f=180^@-theta`
`W=U_f-U_i`
`=-Mbcos(180^@-theta)-(-MBcos180^@)`
`=Mbcostheta-MB`
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