The straight wire AB carries a current I...

The straight wire `AB` carries a current `I`. The ends of the wire subtend angles `theta_1` and `theta_2` at the point `P` as shown in figure. The magnetic field at the point `P` is

`(mu0I)/(4pia)(sintheta_1-sintheta_2)`

`(mu_0I)/(4pia)(sintheta_1+sintheta_2)`

`(mu_0I)/(4pia)(costheta_1-costheta_2)`

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