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A square loop of side a carries a curren...

A square loop of side a carries a current `I`. The magnetic field at the center of the loop is

A

`(2mu_0Isqrt2)/(pia)`

B

`(mu_0Isqrt2)/(pia)`

C

`(4mu_0Isqrt2)/(pia)`

D

`(mu_0I)/(pia)`

Text Solution

Verified by Experts

The correct Answer is:
A

`B_C=3[mu_0/(4pi) I/(a/2)(sin45^@+sin45^@)]`
`(2sqrt2m_0I)/(pia)`
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