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An electron moves through a uniform magn...

An electron moves through a uniform magnetic fiedl given by `B=B_xhati+(3B_x)hatj`. At a particular instant, the electron has the velocity `v=(2.0hati+4.0hatj)` m/s and the magnetic force acting on its is `(6.4xx10^-19N)hatk` Find `B_x`.

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The correct Answer is:
B
`F=q(vxxB)`
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