An electron in the beam of a TV picture tube is accelerated by a potential difference of `2.00 kV`. Then, it passes through region of transverse magnetic field, where it moves in a circular arc with radius `0.180 m`. at is the magnitude of the field?

Answer

A, C, D

Explanation

`r=sqrt((2qVm))/(Bq)`
`:. B=1/r sqrt((2Vm)/q)`
`=1/0.18 sqrt((2xx2xx10^3x9.1xx10^-31)/(1.6xx10^-19))`
`=8.38xx10^-4TG`