For the situation shown in figure, find the force experienced by side MN of the rectangular loop. Also, find the torque on the loop.

Explanation

`F/L=mu_0/(2pi)(I_1I_2)/a`
`:. F=mu_0/(2pi) (I_2I_2)/aL` (Repulsiong or upwards)
M of the loop is inwards and magnetic field to `I_1` on the plane of loop is outwards. Hence` tau=0` as `tau=MxxB` and angle between two is `180^@`