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The figure shows tow coaxial circulalr l...

The figure shows tow coaxial circulalr loop a1 and 2, which forms same solid angle `theta` at point `O`. If `B_1` and `B_2` are the magnetic fields produced at the point `O` due to loop 1 and 2 respectively, then

A

`B_1/B_2=1`

B

`B_1/B_2=2`

C

`B_1/B_2=8`

D

`B_1/B_2=4`

Text Solution

Verified by Experts

The correct Answer is:
B
`B_1 =(muIR^3)/(2(R^2+x^2)^(3/2))`
`B_2=(mu_I(2R)^2)/(2[(2R)^2+(2x)^2]^(3/2))`
`B_1/B_2=2`
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