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A square loop of side 6 cm carries a cur...

A square loop of side `6 cm` carries a current of `30 A`. Calculate the magnitude of magnetic field `B` at a point `P` lying on the axis of the loop and a distance`sqrt7` cm from centre of the loop.

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The correct Answer is:
A, B, D
`r=sqrt(9+7)=4cm`
`B=mu_0/(4pi)(2sinalpha) `
`=(106i-7)(30/(4xx10^-2))(2xx3/5)`
`=9.0xx10^-5T`

`Net field =4Bsintheta`
`=4xx9.0xx10^-5xx3/4`
`=2.7xx10^-4T`
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