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A rod of length 3l rotated with an angul...

A rod of length `3l` rotated with an angular velocity `omega` as shown in figure. The unfiorm magnetic field `B` is into the paper. Find
(a) `V_(A)-V_(C)` (b) `V_(A) - V_(D)`
`

A

`(Bomega(2l)^2)/4` `(Bomega(2l)^2)/2` `-3Bomegal^2//2`

B

`(Bomega(2l)^2)/2` `(Bomega(2l)^2)/2` `-3Bomegal^2//2`

C

`(Bomega(2l)^2)/2` `(Bomega(2l)^2)/2` `3Bomegal^2//2`

D

`(Bomega(2l)^2)/2` `(Bomega(l)^2)/2` `-3Bomegal^2//2`

Text Solution

Verified by Experts

The correct Answer is:
B
`V_A-V_C=(Bomegal^2)/2`
`V_D-V_C=(Bomega(2l)^2)/2`
From these two equations we find
`V_A-V_D=-3Bomegal^2//2`
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