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The loop shown moves with a velocity v i...

The loop shown moves with a velocity `v` in a uniform magnetic field of magnitude `B`, directed into the paper. The potential differene between point `P` and `Q` is e. Then

A

`e=1/2BLv`

B

`e=BLv`

C

`P` is positive with respect to `Q`

D

`Q` is positive with respect to `P`

Text Solution

Verified by Experts

The correct Answer is:
A, C
`e=Bvl`, where `i=L/2`
for polarity of this motional emf, we can use right hand rule.
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Knowledge Check

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