Home
Class 12
PHYSICS
A light beam travelling in the x- direct...

A light beam travelling in the x- direction is described by the electric field `E_y(300V (m^-1) sin omega (t-(x//c))`. An electron is constrained to move along the y-direction with a speed`(2.0 xx (10^7) m(s^-1))`. Find the maximum electric force and the maximum magnetic force on the electron.

Text Solution

Verified by Experts

Maximum Electric Force
maximum electric field,
`E_0=300 V//m`
maximum electricfoce
`F=qE_0`
`= (1.6xx10^-19)(300)`
`= 4.8xx10^-17 N`
Maximum Magnetic Force
From the equation,
` c=E_0/B_0`
Maximum magnetic field,
or
`B_0 = 300/(3.0xx10^8)=10^-6T`
`:.` maximum magnetic force = `B_0qupsilon`
Substituting the values,we have
maximum magnetic force
`(10^-6)(1.6xx10^-19)(2.0xx10^7)`
` 3.2xx 10^-18 N`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    DC PANDEY|Exercise Exercise 29.1|1 Videos
  • ELECTROMAGNETIC WAVES

    DC PANDEY|Exercise Exercise 29.2|4 Videos
  • ELECTROMAGNETIC WAVES

    DC PANDEY|Exercise Sec C|22 Videos
  • ELECTROMAGNETIC INDUCTION

    DC PANDEY|Exercise Medical entrances gallery|25 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY|Exercise (C) Chapter exercises|50 Videos

Similar Questions

Explore conceptually related problems

A light beam travelling in the x -direction is described by the eectirc field E_(y) = (300 V//m) sin omega(t - x//c) . An electron is constrained to move along the y -direction with a speed of 2.0 xx 10^(7) m//sec . Find the maximum electric force and the maximum magnetic force on the electron.

A light beam travelling in the x-direction is described by the electric field : E_(y) = 270 "sin" omega(t-(x)/(c)). An electron is constrained to move along the y-direction with a speed of 2.0xx10^(7) "ms"^(-1). find the maximum electric force and maximum magnetic force on the electron.

A light beam traveling in the x-direction is described by th electric field E_(y)=300sin omega (t-x/c) . An electron is constarained to move along the y-direction with a speed of 2.0xx10^(7) m/s. Find the maximum electric force (in newton) on the electron.

The expression of electric field for a light beam travelling in the X- direction is E= 250 sin omega ( t - (x)/(c ) ) V//m A proton is travelling along the y-direction with a speed of 2.2 xx 10^7 m//s calculate the maximum electric force and maximum magnetic force on the electron .

A light beam is described by E = 800 sinOmega(t-x/c) . An electron is allowed to move normal to the propagation of light beam with a speed of 3xx10^7ms^(-1) . What is the maximum magnetic force exerted on the electron ?

Electromagnetic wave is travelling along X - axis and its electric field is found to oscillate along Y -axis amplitude 210 V/m what will be the amplitude of magnetic field ? One electron is constrained to move along Z- axis with a speed of 3xx 10^(-7) m/s . find maximum electric and magnetic force on electron .

A laser beam has intensity 2.5 xx (10^14)W (m^-2). Find the amplitudes of electric and magnetic fields in the beam.

A beam of light travelling along x-axis is described by the magnetic field, E_y=(600 Vm^-1) sin omega (t-x//c) Calculating the maximum electric and magnetic forces on a charge q=2e, moving along y-axis with a speed of 3xx10^7m//s , where e=1.6xx10^(-19)C .

A beam of light travelling aling x-axis is described by the magnetic field, B _(o) =5.2 xx 10 ^(-9) T sin omega (t - x//c). Then, (Charge on electron =1. 6 xx 10 ^(-19) C)

A beam of light travelling along x-axis is described by the magnetic field, B_z=5xx10^-9Tsin omega (t-x//c) Calculating the maximum electric and magnetic forces on a charge, i.e. alpha particle moving along y-axis with a speed of 3xx10^7m//s , charge on electron = 1.6xx10^-19C