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One requires 11eV of energy to dissociat...

One requires `11eV` of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in.

A

visible region

B

infrared region

C

ultraviolet region

D

microwave region

Text Solution

Verified by Experts

The correct Answer is:
C
`11` eV energy radiation lies in UV range.
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When an electric discharge is passed through hydrogen gas, the hydrogen molecules dissociate to produce excited to produce excited hydrogen atoms. These excited atoms emit electromagnetic radiation of discrete frequencies which can be given by the general formula vecv=109677[(1)/(n_(i)^(2))-(1)/(n_(f)^(2))] What points of Bohr's model of an atom can be used to arrive at this formula? Based on these points derive the above formula giving description of each step and each term.

When an electric discharge is passed through hydrogen gas, the hydrogen molecules dissociate to produce excited hydrogen atoms. These excited atoms emit electromagnetic radiation of discrete frequencies which can be given by the general formula bar(v) = 109677 [(1)/(n_(i)^(2))- (1)/(n_(2)^(f))] What points of Bohr's model of an atom can be used to arrive at this formula ? Based on these points derive the above formula giving description of each step and each term.

Knowledge Check

  • Find the appropriate electromagnetic radiation required to achieve the dissociation of a carbon monoxide molecule into cabon and oxygen atom which required 11 eV energy:

    A
    visible region
    B
    infrared region
    C
    ultraviolet region
    D
    micorwave region

  • In a carbon monoxide molecule, the carbon and oxygen atoms are separated by a distance of 1.12 xx 10^(-10) m. The distance of the centre of mass from the carbon atom is

    A
    `0.48 xx 10^(-10)` m
    B
    `0.51 xx 10^(-10) m`
    C
    `0.56 xx 10^(-10) m`
    D
    `0.64 xx 10^(-10)` m

  • In a carbon monoxide molecule, the carbon and the oxygen atoms are separted by a distance 1.12 xx 10^(10) m. The distance of the centre of mass from the carbon atom is

    A
    ` 0.64 xx 10^(-10)m`
    B
    `0.56xx10^(-6) `m
    C
    `0.51 xx 10^(-10) m`
    D
    `0.48 xx 10^(-10)` m

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