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The charge on a parallel plate capacitor...

The charge on a parallel plate capacitor varies as `=q_0 cos 2pi ft`. The plates are very large and close together (area=a,separation=d). Neglecting the edge effects, find the displacement current through the capacitor.

Text Solution

Verified by Experts

The correct Answer is:
B
`i_d=i_c=(dq)/(dt)`
`=-2piq_0f sin (2pift)`.
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Knowledge Check

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