In the figure, light is incident on a thin lens as shown. The radius of curvature for both the surfaces is R. Determine the focal length of this system.
Text Solution
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For refraction at first surface, `mu_2/v_1-mu_1/-oo=(mu_2-mu_1)/(+R)`………(i) For refraction at second surface, `mu_3/v_2-mu_2/v_1=(mu_3-mu_2)/(+R)` …………(ii) Adding Eqs. (i) and (ii), we get `mu_3/v_2-(mu_2-mu_1)/R or v_2=(mu_3R)/(mu_3-mu_1)` Therefore, focal length of the given lens system is `f=(mu_3R)/(mu_3-mu_1)`
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