Light is incident normally on the short face of a `30^@-60^@-90^@` prism. A liquid is poured on the hypotenuse of the prism. If the refractive index of the prism is `sqrt(3)`, find the maximum refractive index of the liquid so that light is totally reflected.

Answer

A

Explanation

`"Critical angle"=i=60^@=theta_C`
`sin theta_C=mu_R/mu_D rArr sin 60^@=mu/sqrt3`
Solving, we get, `mu=1.5`