A bird is flying over a swimming pool at a height of `2m` from the water surface. If the bottom is perfectly plane reflecting surface and depth of swimming pool is `1m,` then the distance of final image of bird from the bird itself is `mu_w=4//3`

Options

A. `11/3 m`
B. `23/3 m`
C. `11/4 m`
D. `11/2 m`

Answer

D

Explanation

`h_(app)=muh=4/3xx2=8/3m`
`Distance from mirror=1+h_(app)=11/3m.` So, mirror
will make image at same distance (`=11//3m` from itself).
Now in third refraciton, depth of second
image,
`d=11/3+1=14/3 m`
`d_(app)=d/mu=14/3xx3/4=7/2m`
The desired distance is therefore,
`(d_(app)+h)`
or `(7/2+2)m or 11/2m`