A plano-convex lens P and a concavo-convex lens Q are in contact as shown in figure. The refractive index o fthe material of the lens P and Q is `1.8 and 1.2` respectively. The radius of curvature of the concave surface of the lens Q is double the radius of curvature of the convex surface. The convex surface of Q is silvered. The radius of curvature of common surface is
A
`48 cm`
B
`24 cm`
C
`12 cm`
D
`8 cm`
Text Solution
Verified by Experts
The correct Answer is:
A
Focal length of lenses is `1/F=(1.8-1)(1/oo-1/(-2R))+(1.2-1)(1/(-2R)-1/(-R))` `F=2R` Now combined power of system, `P=2P_L+P_m` or `-1/f=2P_L+P_m` or `1/8=2(1/(2R))+2/R` `or R=24 cm` `:.` Radius of curvature of common surface `=2R=48 cm`
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