In YDSE, the two slits are separated by 0.1 mm and they are
0.5 m from the screen. The wavelength of light used is 5000 Å. Find the distance
between 7th maxima and 11 th mimima on the upper side of screen.

Explanation

To solve the problem of finding the distance between the 7th maxima and the 11th minima in Young's Double Slit Experiment (YDSE), we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Distance between slits (d) = 0.1 mm = \(0.1 \times 10^{-3}\) m = \(1 \times 10^{-4}\) m
- Distance from slits to screen (D) = 0.5 m
- Wavelength of light (λ) = 5000 Å = \(5000 \times 10^{-10}\) m = \(5 \times 10^{-7}\) m
...