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A parallel beam of light (lambda= 5000 Å...

A parallel beam of light `(lambda= 5000 Å)` is incident at an angle `theta=30^@` with the normal to the slit plane in a Young's double slit experiment. The intensity due to each slit is I_0. Point O is equidistant from `S_1 and S_2`. The distance between slits is 1mm.

A

the intensity at P is `4I_0`.

B

The intensity at O is zero.

C

The intensity at a point on the screen 2mm above O is `4I_0`.

D

The intensity at a point on the screen 4 mm above O is zero.

Text Solution

Verified by Experts

The correct Answer is:
A
`Deltax_0=dsin theta = (10^(-3))(1/2)`
` = 5xx 10^-4m = (10^3) lambda`
Since, `Deltax_0` is integer multiple of `lambda`, it will produce
maximum intensity or `4I_0` at O.
`omega = (lambdaD)/d = ((5xx10^(-7))(2))/(10^-3)`
`=10^(-3)m = 1mm`
At 4 mm, we will get 4th order maxima.
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