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Neon-23 decays in the following way, 1...

Neon-23 decays in the following way,
`_10^23Nerarr_11^23Na+ _(-1)^0e+barv`
Find the minimum and maximum kinetic energy that the beta particle`(_(-1)^0e)`can have. The atomic masses of `^23Ne` and `^23 Na` are `22.9945u` and `22.9898u`, respectively.

Text Solution

Verified by Experts

The correct Answer is:
D
Here, atomic masses are given (not the nuclear masses), but still we can use them for calculating the mass defect because mass of electrons get cancelled both sides. Thus,
Mass defect `Deltam=(22.9945-22.9898)=0.0047u`
`Q=(0.0047u)(931.5MeV//u)`
`=4.4 MeV`
Hence, the energy of beta particles can range from 0 to 4.4 MeV.
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