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The half-life of ^215At is 100mus. The t...

The half-life of `^215At` is `100mus`. The time taken for the activity of a sample of `^215At` to decay to `1/16th` of its initial value is

A

`400 mus`

B

`63mus`

C

`40 mus`

D

`300 mus`

Text Solution

Verified by Experts

The correct Answer is:
A
`R=R_0(1/2)^n` …(i)
Here, R= activity of radioactive substance after n half-lives `=R_0/16` (given)
Substituting in Eq. (i), we get `n=4`
`:.` `t=(n)t_(1//2)=(4)(100mus)=400mus`
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