Order of magnitude of density of uranium nucleus is , [m = 1.67 xx 10^(-27 kg]`

Options

A. (a) `10^20kg//m^3`
B. (b) `10^17 kg//m^3`
C. (c) `10^14 kg//m^3`
D. (d) `10^11kg//m^3`

Answer

B

Explanation

Radius of a nucleus is given by
`R=R_0A^(1/3) (where, `R_0=1.25xx10^-15m)
`=1.25 A^(1//3)xx10^(-15)m`
Here, A is the mass number and mass of proton `=A(1.67xx10^-27kg)`
`:.` Density, `rho=(mass)/(volume)=(m)/(4/3piR^3)`
`=(A(1.67xx10^-27kg))/(A(1.25xx10^-15m)^3)`
or `rho=2.0xx10^17kg//m^3`