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The binding energy of alpha-particle is ...

The binding energy of `alpha`-particle is
( if `m_p=1.00785u`, `m_n=1.00866u` and `m_alpha=4.00274u`)

A

(a) 56.42 MeV

B

(b) 2.821 MeV

C

(c) 28.21 MeV

D

(d) 32.4 MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Binding energy `=(Deltam)xx931.5 MeV`
`=[2xx1.00785+2xx1.00866-4.00274]xx931.5`
`=28.2 MeV`
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