Obtain the amount of `^60Co` necessary to provide a radioactive source of 8.0 Ci strength. The half-life of `^60Co` is 5.3 years?

Answer

A, C

Explanation

`:'` `R=lambdaN`
`:'` `N=R/lambda=(R)/((1n2)//t_(1//2))=(Rt_(1//2))/(1n2)`
`=((8xx3.7xx10^10)(5.3)(365)(24)(3600))/(0.693)`
`7.14xx10^19`
`m=(7.14xx10^9)/(6.02xx10^23)xx60g`
`=7.11xx10^-3g`