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At t=0, number of radioactive nuclei of ...

At `t=0`, number of radioactive nuclei of a radioactive substance are x and its radioactivity is y. Half-life of radioactive substance is T. Then,

A

(a) `x/y` is constant throughout

B

(b) `x/ygtT`

C

(c) value of `xy` remains half after one half-life

D

(d) value of `xy` remains one fourth after one half-life

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`y=lambdax=(1n2)/(T).x`
`x/y=1/lambda=constant`
`x/y=(T)/(1n2)` or `x/ygtT` (as `1n2=0.693)`
Further,
`xy=x(lambdax)=lambdax^2`
After one half-life, x remains half. Hence, `x^2` remains `1/4th`.
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