Find the current passing through ` 2 Omega `
and ` 4 Omega ` resistance in the circuit shown in figure.

Explanation

To find the current passing through the 2 Ω and 4 Ω resistors in the given circuit, we will analyze the circuit step by step.

### Step 1: Analyze the Circuit
In the circuit, we have a 10V battery connected to two diodes (D1 and D2) and two resistors (2 Ω and 4 Ω).

### Step 2: Determine the State of Diodes
- **Diode D1** is connected in the forward direction (positive terminal of the battery to the anode of D1), which means it will conduct current.
- **Diode D2** is connected in the reverse direction (negative terminal of the battery to the anode of D2), which means it will not conduct current.

### Step 3: Current Flow Analysis
Since D2 is reverse-biased, it will not allow any current to flow through it. Therefore, the only path for the current is through D1 and the 2 Ω resistor.

### Step 4: Calculate the Current Through the 2 Ω Resistor
Using Ohm's Law (V = IR), we can find the current flowing through the 2 Ω resistor. The voltage across the 2 Ω resistor is equal to the voltage of the battery since D2 does not conduct.

- Voltage (V) = 10V
- Resistance (R) = 2 Ω

Using Ohm's Law:
\[ I = \frac{V}{R} = \frac{10V}{2Ω} = 5A \]

### Step 5: Current Through the 4 Ω Resistor
Since the current can only flow through the 2 Ω resistor (due to D2 being reverse-biased), the current through the 4 Ω resistor is 0 A.

### Summary of Results
- Current through the 2 Ω resistor: **5 A**
- Current through the 4 Ω resistor: **0 A**