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A change of 8.0 mA in the emitter curren...

A change of 8.0 mA in the emitter current brings a change of 7.9mA in the collector current. How much change in the base current is required to have the same change 7.9 mA in the collector current? Find the values of ` alpha ` and ` beta ` .

Text Solution

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We know that ,
` i_e = i_b + i_c `
`:. Delta i_e = Deltai_(b)+Delta i_c `
or , `Delta i_b = Delta i_e - Delta i_c `
Substituting the given values of the question ,
` Delta i_b = (8.0 - 7.9) mA = 0.1 mA `
Hence , a change of 0.1 mA in the base current is required to have a change of 7.9 mA in the collector current .
Further , ` alpha = i_c / i_e or (Delta i_c )/ (Delta i_e) = 7.9 / 8.0 `
` = 0.99 `
` beta = i_c / i_b or (Delta i_c )/( Delta i_b )= 7.9 / 0.1 `
` = 79 `
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