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An n-p-n transistor in a common - emitte...

An n-p-n transistor in a common - emitter mode is used as a simple voltage amplifier with a collector current of 4 mA. The positive terminal of a 8 V battery is connected to the collector through a load resistance ` R_L ` and to the base through a resistance ` R_B ` . The collector - emitter voltage ` V_(CE) = 4 V` , the base - emitter voltage ` V_(BE) = 0.6 V` and the current amplification factor ` beta = 100 ` . Calculate the values of ` R_L ` and `R_B` .

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The correct Answer is:
A
Given , `i_c = 4 mA `
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Applying Kirchhoffs second law in loop 1, we have
`V_(CE) = 8 - i_c R_L`
`:. R_L = 8 - V_(CE) / i_c = (8 - 4)/ (4xx 10^(-3)) `
` = 1000 Omega `
` = 1 k Omega `
Further, ` beta = i_c / i_b `
` :. i_b = i_c / beta = (4 xx 10^(-3)) / 100 A = 40 mu A `
Now, ` V_(BE) = 8 - i_b R_B `
`:. R_B = (8 - V_(BE)) / i_b `
`= (8 -0.6 )/( 40 xx 10^(-6) )`
` = 1.85 xx 10^(5) Omega ` .
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