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(a) A parallel plate capacitor of plate ...

(a) A parallel plate capacitor of plate area `2m^(2)` and pltae separation `5xx8.85mm` is cahrged to `200V` in vacuum. Comute the capacitance, charge, charge density and electric field.
(b) The charging is removed and space between the plates is filled with a dielectric `(K=5)`. computer new capacitance, the `p.d`., electric field and induced charge at the surface of dielectric slab.
(c) If now the dielectric sheet is removed and replaced by two sheets, one `2xx8.85mm` thick of dielectric constant `4`, and the other `3xx8.85mm` thick of dielectric constant `2`, compute electric field in each dielectric, the potential difference across the capacitor and its capacitance.

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