1 kcal of heat flowing through a rod of iron.When the rod is cut down to 4 pieces then what will be the heat flowing through each piece having same differential temperature ?

Options

A. 1/2 Kcal
B. 1/4 kcal
C. 1 Kcal
D. 1/15 Kcal

Answer

C

Explanation

We know that the heat flowing throug a conductor is given by
`Q/t=-KA((d theta)/(dx))`
`implies Q=-KA((d theta)/(dx))t`

Where K=thermal conductivity of the material
A=area of cross-section
`(d theta)/(dx)` =temperature gradient
t=time
Now if we cut the rod into 4 pieces. A remains same K remains same , `(d theta)/(dx)` is said to be same , so for same time t, Q is going to be same as earlier.