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Given that C+O(2)rarrCO(2),DeltaH^(@)=-x...

Given that `C+O_(2)rarrCO_(2),DeltaH^(@)=-xKJ` and `2CO+O_(2)rarr2CO_(2),DeltaH^(@)=-yKJ` The enthalpy of formation of carbon monoxide will be

A

b-2a

B

`(2a-b)/(2)`

C

`(b-2a)/(2)`

D

2a-b

Text Solution

Verified by Experts

The correct Answer is:
C

`C + O_(2) to CO_(2), DeltaH^(@)=-aKJ`
`2CO+O_(2) to 2CO_(2) , DeltaH^(@)=-bKJ`
Formation of CO can be written as :
`C + (1)/(2)O_(2) to CO, DeltaH^(@)`= ?
Adding equation : `C+O_(2) to CO_(2) , DeltaH^(@) =-aKJ`
`CO_(2) to CO + 1/2 O_(2), DeltaH^(@)=b/2 KJ`
We get `DeltaH_(f)^(@)(CO) =b/2 -a =(b-2a)/(2)`
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