`dsp^(2)` hybridisation is found in

Options

A. `[NiCl_(4)]^(3-)`
B. `[COCl_(4)]^(2-)`
C. `[CuCl_(4)]^(3-)`
D. `[PtCl_4]^(2-)`

Answer

B

Explanation

Electronic configuration of Co :
`Co(Z=27): 4s^(2)3d^(7)`
`Co^(2+) :3d^(7)` ,brgt
Therefore, hybridisation is `dsp^(2)` and structure is square planar.