A solid `AB` has `NaCl` structure. If the radius of the cation `A` is `100` pm, what is the radius of anion `B`?

Options

A. 190.47
B. 540.13
C. 525
D. 78.12

Answer

A

Explanation

NaCl type structure is also called face centred cubic lattice. Here the radius ratio `(r_(c)//r_(a))` ranges from 0.414 to 0.732.
radius ratio =`(r_(c))/(r_(a))=("radius of cation")/("radius of anion")`
`implies `radius of anion `(B^(-))=("radius of "A^(+))/("radius ratio")`
`=(100)/(0.414)` to `(100)/(0.732)`
=241.5 to 136.6