The number of electrons delivered at the cathode during electrolysis by a current of `1` ampere in 60 seconds is (charger on electron `= 1.60 xx 10^(-19)C`)

Options

A. `3.74xx10^(20)`
B. `6.0 xx 10^(23)`
C. `7.48 xx 10^(21)`
D. `6.0 xx 10^(20)`

Answer

A

Explanation

Charge=current `xx` time
charge , `Q=1A xx 60 ` sec
=60 coulumb
Now,
96500 C charge is carried by `6.023 xx 10^(23)` electron
`implies 60 ` C charge `=(6.023xx10^(23))/(96500)xx60 ` electrons
`=3.74xx10^(20)` electrons