The weight of one molecules of a compound ` C_(60)H_(122)` is

Options

A. `1.2 xx 10^(-20) ` g
B. `2.025 xx 10^(23) g `
C. `1.4 xx 10^(-21) g `
D. `6.023 xx 10^(23) g `

Explanation

To find the weight of one molecule of the compound \( C_{60}H_{122} \), we will follow these steps:

### Step 1: Calculate the Molecular Weight
1. **Identify the number of atoms**: The compound \( C_{60}H_{122} \) contains 60 carbon (C) atoms and 122 hydrogen (H) atoms.
2. **Use atomic weights**: The atomic weight of carbon is approximately 12 g/mol, and the atomic weight of hydrogen is approximately 1 g/mol.
3. **Calculate the total weight of carbon**:
\[ \text{Weight of Carbon} = 60 \times 12 = 720 \text{ g/mol} \]
4. **Calculate the total weight of hydrogen**:
\[ \text{Weight of Hydrogen} = 122 \times 1 = 122 \text{ g/mol} \]
5. **Add the weights together to find the molecular weight**:
\[ \text{Molecular Weight} = 720 + 122 = 842 \text{ g/mol} \]

### Step 2: Calculate the Weight of One Molecule
1. **Use Avogadro's number**: Avogadro's number is \( 6.022 \times 10^{23} \) molecules/mol.
2. **Calculate the weight of one molecule**:
\[ \text{Weight of one molecule} = \frac{\text{Molecular Weight}}{\text{Avogadro's number}} = \frac{842 \text{ g/mol}}{6.022 \times 10^{23} \text{ molecules/mol}} \]
3. **Perform the calculation**:
\[ \text{Weight of one molecule} \approx \frac{842}{6.022 \times 10^{23}} \approx 1.4 \times 10^{-21} \text{ grams} \]

### Conclusion
The weight of one molecule of the compound \( C_{60}H_{122} \) is approximately \( 1.4 \times 10^{-21} \) grams.