The heat of neutrasation of a strong acid and a strong alkali is `57.0KJ mol^(-1)` . The heat released when `0.5` mole of `HNO_(3)` solution is mixed with `0.2` mole of `KOH` is

Options

A. 11.5 kJ
B. 34.5 kJ
C. 23.5 kJ
D. 58.8 kJ

Answer

A

Explanation

Heat of neurtralization `(DeltaH)=57kJ`, volume of `HNO_(3)=0.5` mole and volume of NaOH=0.2 mole. When `HNO_(3)` solution is added to NaOH solution, then 0.2 mole of `HNO_(3)` solution will combine with 0.2 mole of `OH^(-) ` ions of `NaOH` solution .
`:.` Heat released =`DeltaH xx 0.2 =57xx0.2=11.4 kJ`.