If an electron and a photon propagate in the form of waves having the same wavelength , it implies that they have the same

Options

A. Energy
B. Momentum
C. Velocity
D. Angular momentum

Answer

B

Explanation

The de-Broglie wavelength of a particle or a photon is given by `lamda = h//p`
Where h is the Planck's constant and p is the momentum. As the electron and the photon are having the same wavelength `lamda`, the momentum of both of them will be the same.